Optimal. Leaf size=136 \[ -\frac {3 i b^2 \text {Li}_2\left (1-\frac {2}{\frac {i c}{x}+1}\right ) \left (a+b \cot ^{-1}\left (\frac {x}{c}\right )\right )}{c}-\frac {i \left (a+b \cot ^{-1}\left (\frac {x}{c}\right )\right )^3}{c}-\frac {\left (a+b \cot ^{-1}\left (\frac {x}{c}\right )\right )^3}{x}-\frac {3 b \log \left (\frac {2}{1+\frac {i c}{x}}\right ) \left (a+b \cot ^{-1}\left (\frac {x}{c}\right )\right )^2}{c}-\frac {3 b^3 \text {Li}_3\left (1-\frac {2}{\frac {i c}{x}+1}\right )}{2 c} \]
[Out]
________________________________________________________________________________________
Rubi [B] time = 2.36, antiderivative size = 551, normalized size of antiderivative = 4.05, number of steps used = 82, number of rules used = 23, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.438, Rules used = {5035, 2454, 2389, 2296, 2295, 6715, 2430, 2416, 2396, 2433, 2374, 6589, 2411, 2346, 2301, 6742, 43, 2394, 2393, 2391, 2375, 2317, 2425} \[ \frac {3 b^2 \text {PolyLog}\left (2,-\frac {-x+i c}{2 x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )}{2 c}+\frac {3 b^3 \text {PolyLog}\left (3,-\frac {-x+i c}{2 x}\right )}{2 c}+\frac {3 b^3 \text {PolyLog}\left (3,\frac {x+i c}{2 x}\right )}{2 c}-\frac {3 b^3 \log \left (1+\frac {i c}{x}\right ) \text {PolyLog}\left (2,\frac {x+i c}{2 x}\right )}{2 c}-\frac {3 b^2 \log ^2\left (1+\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )}{8 c}-\frac {3 i b^2 \log ^2\left (1+\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )}{8 x}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}+\frac {3 b \log \left (1+\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {3 i b \log \left (1+\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 x}-\frac {3 b \log \left (\frac {x+i c}{2 x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2}{4 c}-\frac {i \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 c}-\frac {b^3 \left (1+\frac {i c}{x}\right ) \log ^3\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 b^3 \log ^2\left (1+\frac {i c}{x}\right ) \log \left (-\frac {-x+i c}{2 x}\right )}{4 c} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
Rule 43
Rule 2295
Rule 2296
Rule 2301
Rule 2317
Rule 2346
Rule 2374
Rule 2375
Rule 2389
Rule 2391
Rule 2393
Rule 2394
Rule 2396
Rule 2411
Rule 2416
Rule 2425
Rule 2430
Rule 2433
Rule 2454
Rule 5035
Rule 6589
Rule 6715
Rule 6742
Rubi steps
\begin {align*} \int \frac {\left (a+b \tan ^{-1}\left (\frac {c}{x}\right )\right )^3}{x^2} \, dx &=\int \left (\frac {\left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 x^2}+\frac {3 i b \left (-2 i a+b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x^2}-\frac {3 i b^2 \left (-2 i a+b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x^2}+\frac {i b^3 \log ^3\left (1+\frac {i c}{x}\right )}{8 x^2}\right ) \, dx\\ &=\frac {1}{8} \int \frac {\left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{x^2} \, dx+\frac {1}{8} (3 i b) \int \frac {\left (-2 i a+b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{x^2} \, dx-\frac {1}{8} \left (3 i b^2\right ) \int \frac {\left (-2 i a+b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{x^2} \, dx+\frac {1}{8} \left (i b^3\right ) \int \frac {\log ^3\left (1+\frac {i c}{x}\right )}{x^2} \, dx\\ &=-\left (\frac {1}{8} \operatorname {Subst}\left (\int (2 a+i b \log (1-i c x))^3 \, dx,x,\frac {1}{x}\right )\right )-\frac {1}{8} (3 i b) \operatorname {Subst}\left (\int (-2 i a+b \log (1-i c x))^2 \log (1+i c x) \, dx,x,\frac {1}{x}\right )+\frac {1}{8} \left (3 i b^2\right ) \operatorname {Subst}\left (\int (-2 i a+b \log (1-i c x)) \log ^2(1+i c x) \, dx,x,\frac {1}{x}\right )-\frac {1}{8} \left (i b^3\right ) \operatorname {Subst}\left (\int \log ^3(1+i c x) \, dx,x,\frac {1}{x}\right )\\ &=-\frac {3 i b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x}-\frac {3 i b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x}-\frac {i \operatorname {Subst}\left (\int (2 a+i b \log (x))^3 \, dx,x,1-\frac {i c}{x}\right )}{8 c}-\frac {b^3 \operatorname {Subst}\left (\int \log ^3(x) \, dx,x,1+\frac {i c}{x}\right )}{8 c}-\frac {1}{8} (3 b c) \operatorname {Subst}\left (\int \frac {x (-2 i a+b \log (1-i c x))^2}{1+i c x} \, dx,x,\frac {1}{x}\right )+\frac {1}{4} \left (3 b^2 c\right ) \operatorname {Subst}\left (\int \frac {x (-2 i a+b \log (1-i c x)) \log (1+i c x)}{1-i c x} \, dx,x,\frac {1}{x}\right )+\frac {1}{4} \left (3 b^2 c\right ) \operatorname {Subst}\left (\int \frac {x (-2 i a+b \log (1-i c x)) \log (1+i c x)}{1+i c x} \, dx,x,\frac {1}{x}\right )-\frac {1}{8} \left (3 b^3 c\right ) \operatorname {Subst}\left (\int \frac {x \log ^2(1+i c x)}{1-i c x} \, dx,x,\frac {1}{x}\right )\\ &=-\frac {i \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 c}-\frac {3 i b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x}-\frac {3 i b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x}-\frac {b^3 \left (1+\frac {i c}{x}\right ) \log ^3\left (1+\frac {i c}{x}\right )}{8 c}-\frac {(3 b) \operatorname {Subst}\left (\int (2 a+i b \log (x))^2 \, dx,x,1-\frac {i c}{x}\right )}{8 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \log ^2(x) \, dx,x,1+\frac {i c}{x}\right )}{8 c}-\frac {1}{8} (3 b c) \operatorname {Subst}\left (\int \left (-\frac {i (-2 i a+b \log (1-i c x))^2}{c}+\frac {(-2 i a+b \log (1-i c x))^2}{c (-i+c x)}\right ) \, dx,x,\frac {1}{x}\right )+\frac {1}{4} \left (3 b^2 c\right ) \operatorname {Subst}\left (\int \left (-\frac {(2 a+i b \log (1-i c x)) \log (1+i c x)}{c}+\frac {(-2 i a+b \log (1-i c x)) \log (1+i c x)}{c (-i+c x)}\right ) \, dx,x,\frac {1}{x}\right )+\frac {1}{4} \left (3 b^2 c\right ) \operatorname {Subst}\left (\int \left (\frac {(2 a+i b \log (1-i c x)) \log (1+i c x)}{c}+\frac {(-2 i a+b \log (1-i c x)) \log (1+i c x)}{c (i+c x)}\right ) \, dx,x,\frac {1}{x}\right )-\frac {1}{8} \left (3 b^3 c\right ) \operatorname {Subst}\left (\int \left (\frac {i \log ^2(1+i c x)}{c}+\frac {\log ^2(1+i c x)}{c (i+c x)}\right ) \, dx,x,\frac {1}{x}\right )\\ &=-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {i \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 c}-\frac {3 i b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x}+\frac {3 b^3 \left (1+\frac {i c}{x}\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x}-\frac {b^3 \left (1+\frac {i c}{x}\right ) \log ^3\left (1+\frac {i c}{x}\right )}{8 c}+\frac {1}{8} (3 i b) \operatorname {Subst}\left (\int (-2 i a+b \log (1-i c x))^2 \, dx,x,\frac {1}{x}\right )-\frac {1}{8} (3 b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2}{-i+c x} \, dx,x,\frac {1}{x}\right )+\frac {1}{4} \left (3 b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log (1+i c x)}{-i+c x} \, dx,x,\frac {1}{x}\right )+\frac {1}{4} \left (3 b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log (1+i c x)}{i+c x} \, dx,x,\frac {1}{x}\right )-\frac {1}{8} \left (3 i b^3\right ) \operatorname {Subst}\left (\int \log ^2(1+i c x) \, dx,x,\frac {1}{x}\right )-\frac {1}{8} \left (3 b^3\right ) \operatorname {Subst}\left (\int \frac {\log ^2(1+i c x)}{i+c x} \, dx,x,\frac {1}{x}\right )+\frac {\left (3 i b^2\right ) \operatorname {Subst}\left (\int (2 a+i b \log (x)) \, dx,x,1-\frac {i c}{x}\right )}{4 c}-\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1+\frac {i c}{x}\right )}{4 c}\\ &=\frac {3 a b^2}{2 x}+\frac {3 i b^3}{4 x}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {i \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 c}-\frac {3 b^3 \left (1+\frac {i c}{x}\right ) \log \left (1+\frac {i c}{x}\right )}{4 c}-\frac {3 i b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x}+\frac {3 b^3 \left (1+\frac {i c}{x}\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x}-\frac {b^3 \left (1+\frac {i c}{x}\right ) \log ^3\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 b^3 \log ^2\left (1+\frac {i c}{x}\right ) \log \left (-\frac {i c-x}{2 x}\right )}{8 c}-\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (\frac {i c+x}{2 x}\right )}{8 c}-\frac {1}{4} \left (3 i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log \left (\frac {1}{2} i (-i+c x)\right )}{1-i c x} \, dx,x,\frac {1}{x}\right )+\frac {1}{4} \left (3 i b^3\right ) \operatorname {Subst}\left (\int \frac {\log (1+i c x) \log \left (-\frac {1}{2} i (i+c x)\right )}{1+i c x} \, dx,x,\frac {1}{x}\right )-\frac {(3 b) \operatorname {Subst}\left (\int (-2 i a+b \log (x))^2 \, dx,x,1-\frac {i c}{x}\right )}{8 c}+\frac {\left (3 b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (2-x)) \log (x)}{x} \, dx,x,1+\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^2\right ) \operatorname {Subst}\left (\int \frac {\log (2-x) (-2 i a+b \log (x))}{x} \, dx,x,1-\frac {i c}{x}\right )}{4 c}-\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \log ^2(x) \, dx,x,1+\frac {i c}{x}\right )}{8 c}-\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1-\frac {i c}{x}\right )}{4 c}\\ &=\frac {3 a b^2}{2 x}-\frac {3 b^3 \left (1-\frac {i c}{x}\right ) \log \left (1-\frac {i c}{x}\right )}{4 c}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {i \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 c}-\frac {3 b^3 \left (1+\frac {i c}{x}\right ) \log \left (1+\frac {i c}{x}\right )}{4 c}+\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x}-\frac {3 b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x}-\frac {b^3 \left (1+\frac {i c}{x}\right ) \log ^3\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 b^3 \log ^2\left (1+\frac {i c}{x}\right ) \log \left (-\frac {i c-x}{2 x}\right )}{8 c}-\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (\frac {i c+x}{2 x}\right )}{8 c}+\frac {(3 b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (x))^2}{2-x} \, dx,x,1-\frac {i c}{x}\right )}{8 c}+\frac {\left (3 b^2\right ) \operatorname {Subst}\left (\int (-2 i a+b \log (x)) \, dx,x,1-\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (\frac {1}{2} i (-2 i+i x)\right ) (-2 i a+b \log (x))}{x} \, dx,x,1-\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \frac {\log ^2(x)}{2-x} \, dx,x,1+\frac {i c}{x}\right )}{8 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1+\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \frac {\log \left (-\frac {1}{2} i (2 i-i x)\right ) \log (x)}{x} \, dx,x,1+\frac {i c}{x}\right )}{4 c}\\ &=-\frac {3 i b^3}{4 x}-\frac {3 b^3 \left (1-\frac {i c}{x}\right ) \log \left (1-\frac {i c}{x}\right )}{4 c}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {i \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 c}+\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x}-\frac {3 b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x}-\frac {b^3 \left (1+\frac {i c}{x}\right ) \log ^3\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 b^3 \log ^2\left (1+\frac {i c}{x}\right ) \log \left (-\frac {i c-x}{2 x}\right )}{4 c}-\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (\frac {i c+x}{2 x}\right )}{4 c}+\frac {3 b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \text {Li}_2\left (-\frac {i c-x}{2 x}\right )}{4 c}-\frac {3 b^3 \log \left (1+\frac {i c}{x}\right ) \text {Li}_2\left (\frac {i c+x}{2 x}\right )}{4 c}+\frac {\left (3 b^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right ) (-2 i a+b \log (x))}{x} \, dx,x,1-\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1-\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right ) \log (x)}{x} \, dx,x,1+\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2\left (\frac {x}{2}\right )}{x} \, dx,x,1-\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2\left (\frac {x}{2}\right )}{x} \, dx,x,1+\frac {i c}{x}\right )}{4 c}\\ &=-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {i \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 c}+\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x}-\frac {3 b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x}-\frac {b^3 \left (1+\frac {i c}{x}\right ) \log ^3\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 b^3 \log ^2\left (1+\frac {i c}{x}\right ) \log \left (-\frac {i c-x}{2 x}\right )}{4 c}-\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (\frac {i c+x}{2 x}\right )}{4 c}+\frac {3 b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \text {Li}_2\left (-\frac {i c-x}{2 x}\right )}{2 c}-\frac {3 b^3 \log \left (1+\frac {i c}{x}\right ) \text {Li}_2\left (\frac {i c+x}{2 x}\right )}{2 c}+\frac {3 b^3 \text {Li}_3\left (-\frac {i c-x}{2 x}\right )}{4 c}+\frac {3 b^3 \text {Li}_3\left (\frac {i c+x}{2 x}\right )}{4 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2\left (\frac {x}{2}\right )}{x} \, dx,x,1-\frac {i c}{x}\right )}{4 c}+\frac {\left (3 b^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2\left (\frac {x}{2}\right )}{x} \, dx,x,1+\frac {i c}{x}\right )}{4 c}\\ &=-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {3 b \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^2}{8 c}-\frac {i \left (1-\frac {i c}{x}\right ) \left (2 a+i b \log \left (1-\frac {i c}{x}\right )\right )^3}{8 c}+\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (1+\frac {i c}{x}\right )}{8 x}-\frac {3 b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 i b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \log ^2\left (1+\frac {i c}{x}\right )}{8 x}-\frac {b^3 \left (1+\frac {i c}{x}\right ) \log ^3\left (1+\frac {i c}{x}\right )}{8 c}-\frac {3 b^3 \log ^2\left (1+\frac {i c}{x}\right ) \log \left (-\frac {i c-x}{2 x}\right )}{4 c}-\frac {3 b \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right )^2 \log \left (\frac {i c+x}{2 x}\right )}{4 c}+\frac {3 b^2 \left (2 i a-b \log \left (1-\frac {i c}{x}\right )\right ) \text {Li}_2\left (-\frac {i c-x}{2 x}\right )}{2 c}-\frac {3 b^3 \log \left (1+\frac {i c}{x}\right ) \text {Li}_2\left (\frac {i c+x}{2 x}\right )}{2 c}+\frac {3 b^3 \text {Li}_3\left (-\frac {i c-x}{2 x}\right )}{2 c}+\frac {3 b^3 \text {Li}_3\left (\frac {i c+x}{2 x}\right )}{2 c}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 0.19, size = 189, normalized size = 1.39 \[ \frac {-2 \left (a^2 \left (a c+3 b x \log \left (\frac {1}{\sqrt {\frac {c^2}{x^2}+1}}\right )\right )+3 b^2 \tan ^{-1}\left (\frac {c}{x}\right )^2 \left (a c-i a x+b x \log \left (1+e^{2 i \tan ^{-1}\left (\frac {c}{x}\right )}\right )\right )+3 a b \tan ^{-1}\left (\frac {c}{x}\right ) \left (a c+2 b x \log \left (1+e^{2 i \tan ^{-1}\left (\frac {c}{x}\right )}\right )\right )+b^3 (c-i x) \tan ^{-1}\left (\frac {c}{x}\right )^3\right )+6 i b^2 x \text {Li}_2\left (-e^{2 i \tan ^{-1}\left (\frac {c}{x}\right )}\right ) \left (a+b \tan ^{-1}\left (\frac {c}{x}\right )\right )-3 b^3 x \text {Li}_3\left (-e^{2 i \tan ^{-1}\left (\frac {c}{x}\right )}\right )}{2 c x} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
fricas [F] time = 0.52, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{3} \arctan \left (\frac {c}{x}\right )^{3} + 3 \, a b^{2} \arctan \left (\frac {c}{x}\right )^{2} + 3 \, a^{2} b \arctan \left (\frac {c}{x}\right ) + a^{3}}{x^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \arctan \left (\frac {c}{x}\right ) + a\right )}^{3}}{x^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [B] time = 0.25, size = 306, normalized size = 2.25 \[ -\frac {a^{3}}{x}+\frac {i b^{3} \arctan \left (\frac {c}{x}\right )^{3}}{c}-\frac {b^{3} \arctan \left (\frac {c}{x}\right )^{3}}{x}-\frac {3 b^{3} \arctan \left (\frac {c}{x}\right )^{2} \ln \left (\frac {\left (1+\frac {i c}{x}\right )^{2}}{1+\frac {c^{2}}{x^{2}}}+1\right )}{c}+\frac {3 i b^{3} \arctan \left (\frac {c}{x}\right ) \polylog \left (2, -\frac {\left (1+\frac {i c}{x}\right )^{2}}{1+\frac {c^{2}}{x^{2}}}\right )}{c}-\frac {3 b^{3} \polylog \left (3, -\frac {\left (1+\frac {i c}{x}\right )^{2}}{1+\frac {c^{2}}{x^{2}}}\right )}{2 c}+\frac {3 i \arctan \left (\frac {c}{x}\right )^{2} a \,b^{2}}{c}-\frac {3 a \,b^{2} \arctan \left (\frac {c}{x}\right )^{2}}{x}-\frac {6 \ln \left (\frac {\left (1+\frac {i c}{x}\right )^{2}}{1+\frac {c^{2}}{x^{2}}}+1\right ) \arctan \left (\frac {c}{x}\right ) a \,b^{2}}{c}+\frac {3 i \polylog \left (2, -\frac {\left (1+\frac {i c}{x}\right )^{2}}{1+\frac {c^{2}}{x^{2}}}\right ) a \,b^{2}}{c}-\frac {3 a^{2} b \arctan \left (\frac {c}{x}\right )}{x}+\frac {3 a^{2} b \ln \left (1+\frac {c^{2}}{x^{2}}\right )}{2 c} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (a+b\,\mathrm {atan}\left (\frac {c}{x}\right )\right )}^3}{x^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {atan}{\left (\frac {c}{x} \right )}\right )^{3}}{x^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________